Calculate the escape velocity of a satellite launched from the earth's surface if the radius of the earth is 6.4x106m
Question 1 Report
Calculate the escape velocity of a satellite launched from the earth's surface if the radius of the earth is 6.4x106m
Answer Details
Escape velocity is the minimum velocity required by an object to escape the gravitational pull of a planet or a star. To calculate the escape velocity from Earth's surface, we can use the formula:
v = sqrt(2GM/R)
where v is the escape velocity, G is the universal gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.
Plugging in the values, we get:
v = sqrt(2 x 6.67 x 10^-11 x 5.97 x 10^24 / 6.4 x 10^6)
v = sqrt(2 x 9.82 x 10^7)
v = sqrt(1.96 x 10^8)
v = 1.4 x 10^4 m/s
Converting this into kilometers per second, we get:
v = 14 km/s
Therefore, the correct option is "11.3kms^-1".
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning