Consider the reaction represented by the following equation: CuO\(_{(s)}\) + H\(_2\)SO\(_{4(aq)}\) → CuSO\(_{4(aq)}\) + H\(_2\)O\(_{(l)}\). Which of the fol...

Consider the reaction represented by the following equation: CuO\(_{(s)}\) + H\(_2\)SO\(_{4(aq)}\) → CuSO\(_{4(aq)}\) + H\(_2\)O\(_{(l)}\). Which of the following factors will not affect the rate of the reaction?

Answer Details

The factor that will not affect the rate of the reaction is the pressure of the reaction system. The given chemical equation does not involve any gaseous reactants or products, so the pressure of the reaction system will not have any effect on the rate of the reaction. The other factors such as particle size of CuO, concentration of H\(_2\)SO\(_4(aq)\), and temperature of the reacting mixture can all affect the rate of the reaction. - The smaller the particle size of CuO, the larger the surface area, which leads to an increase in the frequency of collisions between reactant particles and hence an increase in the rate of the reaction. - The higher the concentration of H\(_2\)SO\(_4(aq)\), the more the number of H\(_2\)SO\(_4(aq)\) molecules available for reaction with CuO, which leads to an increase in the frequency of collisions and hence an increase in the rate of the reaction. - The higher the temperature of the reacting mixture, the higher the kinetic energy of the reactant molecules, which leads to an increase in the frequency of collisions and hence an increase in the rate of the reaction.