Given that quantity demanded per period of time is a function of price and that the relation is expressed as: Q = 60 - 1/3 P, where Q is quantity demanded a...

Answer Details

(a)Q=60-1/3P  

(i) When price is N30, Q = 60 - 13 $\frac{1}{3}$ (30)
= 60 - 10 , Q = 50

(ii) When price is N210, Q = 60 - 13 $\frac{\mathrm{<span\; style="font-size:\; 16px;">1</span>}}{\mathrm{<span\; style="font-size:\; 16px;">3</span>}}$(210) 
= 60 - 70 = - 10

(iii) When price is N0, Q = 60 -13 $\frac{\mathrm{<span\; style="font-size:\; 16px;">1</span>}}{\mathrm{<span\; style="font-size:\; 16px;">3</span>}}$(0)
3 = 60 -0 = 60 

(b) In (a) (ii) above, the law of demand comes into play here. The law of demand states that, " the higher the price, the lower the quantity demanded". The fact that the price is as high as N210, consumers are not willing to buy more.

(c)(i) P = N (180 - 3Q)
when Q= 0
p = N (180 - 3(0)
= N180 - 0
=N180

(ii) when Q = 60
p= N (180 - 3 (60)
= N (180 - 180) =N0

(iii) when Q = 59
P = N (180 - 3(59)
= N (180 - 177) = N3.