Question 1 Report
A resistance R is connected across the terminal of an electric cell of internal resistance 2Ω and the voltage was reduced to 3/5 of its nominal value.
The value of R is
Answer Details
1 = V/R = E/R+r , if r = 2Ω V = 3/5 E => 3E/5R = E/R+2 i.e 3E(R+2) = 5RE 3RE + 6E = 5RE i.e 3R + 6 = 5R 6 = 5R - 3R => 2r = 6 i.e R = 6/2 = 3Ω