A conductor of length 2m carries a current of 0.8A while kept in a magnetic field of magnetic flux density 0.5T. The maximum force acting on it is

Answer Details

The force acting on a current-carrying conductor in a magnetic field is given by the formula F = BILsinθ, where B is the magnetic flux density, I is the current, L is the length of the conductor, and θ is the angle between the direction of the current and the magnetic field. Since the conductor is perpendicular to the magnetic field, sinθ = 1. Therefore, the maximum force on the conductor is F = BIL = (0.5T)(0.8A)(2m) = 0.8N. Hence, the correct option is 0.8N.