A given mass of gas occupies 2 dm3 at 300k. At what temperature will its volume be doubled keeping the pressure constant?

The problem describes a gas with a constant pressure but a changing volume and temperature. According to Charles's Law, the volume of a fixed mass of gas at constant pressure is directly proportional to its absolute temperature. That is, as the temperature of the gas increases, so does its volume, and vice versa. Using this law, we can set up a proportion between the initial and final temperatures and volumes: (initial volume) / (initial temperature) = (final volume) / (final temperature) We are given the initial volume (2 dm³) and temperature (300 K), and we are looking for the final temperature that will result in double the initial volume (4 dm³). (2 dm³) / (300 K) = (4 dm³) / (final temperature) Solving for the final temperature: final temperature = (4 dm³) x (300 K) / (2 dm³) = 600 K Therefore, the temperature at which the gas's volume will be doubled while keeping the pressure constant is 600 K. The correct answer is "600k".