What volume of oxygen is produced from the decomposition of 2 mole of KCIO3 at s.t.p? [Molar volume of a gas at s.t.p = 22.4 dm3]

Answer Details

The question is asking for the volume of oxygen produced from the decomposition of 2 moles of KCIO3 at s.t.p, given the molar volume of a gas at s.t.p is 22.4 dm3. Firstly, we need to balance the chemical equation for the decomposition of KCIO3: 2KClO3 → 2KCl + 3O2 From the equation, we can see that for every 2 moles of KCIO3, we get 3 moles of O2. Therefore, to find the volume of oxygen produced, we can use the following calculation: Volume of O2 = number of moles of O2 × molar volume of a gas at s.t.p Volume of O2 = 3 mol × 22.4 dm3/mol Solving this equation gives us: Volume of O2 = 67.2 dm3 So the answer is 67.2 dm3. Therefore, the label for the question would be "stoichiometry" and "gas volume calculations".