CO(g) + H2O(g) ? CO2(g) + H2(g) From the reaction above, calculate the standard enthalpies of formation of CO2(g), H2O(g) and CO(g) in kJ mol-1 are -394, -2...

CO(g) + H2O(g) ? CO2(g) + H2(g)

From the reaction above, calculate the standard enthalpies of formation of CO2(g), H2O(g) and CO(g) in kJ mol-1 are -394, -242, and -110 respectively.

Answer Details

CO + H2O ? CO2 + H2 DH = 394 kJ mol-1
-242 + 110 = -352 kJ mol-1
35 = -394 -(352)
= -394 + 352
= -42 kJ mol-1