in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]

Assessment: WAEC SSCE - Physics - 2015 (Objective) Subject: Physics

Question 1 Report

in a nuclear fission process, the mass defect was 1.2 x 10^-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 10⁸ms^-1]

1.08 x 10¹¹J

5.20 x 10¹¹J

1.08 x 10¹²J

2.50 x 10¹³J

Answer Details

The energy released in a nuclear fission process can be calculated using Einstein's famous equation E = mc^2, where E is the energy released, m is the mass defect, and c is the speed of light. Substituting the given values, we have: E = (1.2 x 10^-5 kg) x (3.0 x 10^8 m/s)^2 E = (1.2 x 10^-5 kg) x (9.0 x 10^16 m^2/s^2) E = 1.08 x 10^12 J Therefore, the energy released in the nuclear fission process is 1.08 x 10^12 J. So the answer is (c) 1.08 x 10^12 J.

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Structure Of The Atom (Nigeria Only)

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in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]

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