The terminal voltage of a battery is 4.0V when supplying a current of 2.0A, and 2.0V when supplying a current of 3.0A. The internal resistance of the batter...

Assessment: JAMB UTME - Physics - 1993 Subject: Physics

Question 1 Report

The terminal voltage of a battery is 4.0V when supplying a current of 2.0A, and 2.0V when supplying a current of 3.0A. The internal resistance of the battery is
Answer Details
The internal resistance of the battery can be calculated using the formula: R = (V1 - V2) / (I2 - I1) Where: V1 = voltage of the battery when supplying current I1 V2 = voltage of the battery when supplying current I2 I1 = current supplied to the battery when measuring V1 I2 = current supplied to the battery when measuring V2 Substituting the given values in the above formula, we get: R = (4.0V - 2.0V) / (3.0A - 2.0A) = 2.0Ω Therefore, the internal resistance of the battery is 2.0Ω. Explanation: The internal resistance of a battery is the resistance offered by the electrolyte inside the battery to the flow of current. When a battery is connected to an external circuit, the current flows through the external circuit and through the internal resistance of the battery. The voltage drop across the internal resistance reduces the terminal voltage of the battery. By measuring the terminal voltage of the battery at two different currents, we can calculate the internal resistance of the battery using the formula mentioned above.

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning