When the volume of a given mass of gas is halved and its temperature doubled, the pressure
Question 1 Report
When the volume of a given mass of gas is halved and its temperature doubled, the pressure
Answer Details
According to the ideal gas law, pressure (P), volume (V), and temperature (T) of a gas are related as follows: P x V = n x R x T, where n is the number of moles of the gas and R is a constant.
If the volume of a gas is halved (V/2) and its temperature is doubled (2T), then the new values of P and V can be found by plugging these new values into the ideal gas law:
P x (V/2) = n x R x (2T)
Simplifying this equation, we get:
P/2 = n x R x 2T/V
Multiplying both sides by 2, we get:
P = n x R x 2T/V
Since V is halved, the fraction 2T/V becomes twice as large. Therefore, the pressure (P) of the gas increases by a factor of 2 x 2 = 4.
So, the correct option is "increases by a factor of 4".
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