If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.
Question 1 Report
If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.
Answer Details
To solve this problem, we need to integrate both sides of the equation with respect to x.
dy/dx = 2x - 3
Integrating both sides with respect to x gives:
y = x^2 - 3x + c
where c is the constant of integration.
To find the value of c, we use the fact that y = 3 when x = 0:
3 = 0^2 - 3(0) + c
c = 3
Therefore, the equation of y in terms of x is:
y = x^2 - 3x + 3
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