Question 1 Report
If S = (4t + 3)(t - 2), find ds/dt when t = 5 secs.
Answer Details
s=(4t+3)(t−2) s = ( 4 t + 3 ) ( t − 2 ) dsdt=(4t+3)(1)+(t−2)(4) d s d t = ( 4 t + 3 ) ( 1 ) + ( t − 2 ) ( 4 ) = 4t+3+4t−8 4 t + 3 + 4 t − 8 = 8t - 5 dsdt(t=5secs)=8(5)−5 d s d t ( t = 5 s e c s ) = 8 ( 5 ) − 5 = 40 - 5 = 35 units per sec
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