The nth term of a sequence is given by 22n−1 2 n − 1 . Find the sum of the first four terms.

Question 1 Report

The nth term of a sequence is given by 2 $^{2 n - 1}$ . Find the sum of the first four terms.

170

Answer Details

$T_{n} = 2^{2 n - 1}$
$T_{1} = 2^{2 (1) - 1}$
= 2
$T_{2} = 2^{2 (2) - 1}$
= 8
$T_{3} = 2^{2 (3) - 1}$
= 32
$T_{4} = 2^{2 (4) - 1}$
= 128
$T_{1} + T_{2} + T_{3} + T_{4} = 2 + 8 + 32 + 128$
= 170

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Sequence And Series

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