Find the polynomial if given $q(x) = x^2 - x - 5$, $d(x) = 3x - 1$ and $r(x) = 7$.

Assessment: JAMB UTME - Mathematics - 2019 Subject: General Mathematics

Question 1 Report

^{3}

- 4x

^{2}

- 14x + 12

^{2}

+ 3x - 7

^{3}

+ 4x

^{2}

+ 14x - 12

^{2}

- 3x + 4

Answer Details

Given q(x) [quotient], d(x) [divisor] and r(x) [remainder], the polynomial is gotten by multiplying the quotient and the divisor and adding the remainder.
i.e In this case, the polynomial = (x $^{2}$ - x - 5)(3x - 1) + 7.
= (3x $^{3}$ - x $^{2}$ - 3x $^{2}$ + x - 15x + 5) + 7
= (3x $^{3}$ - 4x $^{2}$ - 14x + 5) + 7
= 3x $^{3}$ - 4x $^{2}$ - 14x + 12

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Find the polynomial if given \(q(x) = x^2 - x - 5\), \(d(x) = 3x - 1\) and \(r(x) = 7\).

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Find the polynomial if given \(q(x) = x^2 - x - 5\), \(d(x) = 3x - 1\) and \(r(x) = 7\).

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