Find the polynomial if given \(q(x) = x^2 - x - 5\), \(d(x) = 3x - 1\) and \(r(x) = 7\).
Question 1 Report
Find the polynomial if given \(q(x) = x^2 - x - 5\), \(d(x) = 3x - 1\) and \(r(x) = 7\).
Answer Details
Given q(x) [quotient], d(x) [divisor] and r(x) [remainder], the polynomial is gotten by multiplying the quotient and the divisor and adding the remainder.
i.e In this case, the polynomial = (x - x - 5)(3x - 1) + 7.
= (3x - x - 3x + x - 15x + 5) + 7
= (3x - 4x - 14x + 5) + 7
= 3x - 4x - 14x + 12
i.e In this case, the polynomial = (x - x - 5)(3x - 1) + 7.
= (3x - x - 3x + x - 15x + 5) + 7
= (3x - 4x - 14x + 5) + 7
= 3x - 4x - 14x + 12
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