ddx[log(4x3−2x)] d d x [ log ⁡ ( 4 x 3 − 2 x ) ] is equal to

Answer Details

To find d/dx[log(4x^3−2x)], we can apply the chain rule of differentiation. Let u = 4x^3−2x, then y = log(u). Applying the chain rule, we have: dy/dx = dy/du * du/dx To find du/dx, we need to differentiate u with respect to x, giving: du/dx = 12x^2 - 2 To find dy/du, we can use the formula for differentiating the natural logarithm, which gives: dy/du = 1/u Putting these together, we have: dy/dx = dy/du * du/dx = 1/u * (12x^2 - 2) = (12x^2 - 2)/(4x^3 - 2x) = 2(6x^2 - 1)/(2x(2x^2 - 1)) Therefore, the answer is (12x^2 - 2)/(4x^3 - 2x), which is equivalent to.