A small object of mass 50 g is released from a point A. Determine the velocity of the object when it reaches a point B, a vertical distance of 30m below A. ...
Question 1 Report
A small object of mass 50 g is released from a point A. Determine the velocity of the object when it reaches a point B, a vertical distance of 30m below A. [g = \(10\ \mathrm{ms}^{-2}\)]
Answer Details
We can solve this problem using the principle of conservation of energy. When the object is at point A, it has some gravitational potential energy given by mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference level. When the object falls to point B, it loses some potential energy, which is converted into kinetic energy. We can write this as:
mgh = (1/2)mv^2
where v is the velocity of the object at point B.
Rearranging the equation, we get:
v = √(2gh)
Substituting the given values, we get:
v = √(2 × 10 × 30) = √600 = 24.5 m/s
Therefore, the velocity of the object when it reaches point B is 24.5 m/s.
So, the correct answer is "24.5 m/s".
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning