You are provided with a potentiometer x y; a jockey, J; a standard resistor, R, and other necessary apparatus. Connect a circuit as shown in the diagram abo...
You are provided with a potentiometer x y; a jockey, J; a standard resistor, R, and other necessary apparatus.
Connect a circuit as shown in the diagram above.
Close the key. Read and record the current 10 when J is not in contact with XY.
Let J make contact with XY at C, such that XC = l= 25 cm. Close the key. Read and record the current l.
Evaluate I\(^{-1}\).
Repeat the procedure for four other values of I = 40, 55, 70, and 85 cm. Tabulate your readings.
Plot a graph of l on the vertical axis against I\(^{-1}\) on the horizontal axis.
From your graph, deduce the value of I when l\(^{-1}\) = 0. Evaluate \(\frac{|O}{1}\)
State two precautions taken to ensure accurate results.
(b)i) Explain what is meant by the potential difference between two points in an electric circuit.
ii. A piece of resistance wire of diameter 0.2m and resistance 7\(\Omega\) has a resistivity of 8.8 x 10\(^{-7}\) \(\Omega\)m. Calculate the length of the wire. [\(\pi\) = \(\frac{22}{7}\)].
(a) Potentiometer (rheostat) current experiment
The circuit is connected as shown, with the standard resistor \(R\) and the ammeter in series with the length \(XC=l\) of the potentiometer wire. With the jockey off the wire the ammeter reads \(I_0\); when the jockey contacts XY at C the current \(I\) is read for each length \(l\), and \(l^{-1}\) is evaluated.
Circuit: cell E, key K and ammeter A in series with the standard resistor R and the length XC = l of the potentiometer wire; jockey J makes contact at C.
Table of readings (\(I_0 = 0.8\ \text{A}\))
S/N
\(l\) (cm)
\(I\) (A)
\(l^{-1}\) (cm\(^{-1}\))
1
25.0
1.20
0.040
2
40.0
1.00
0.025
3
55.0
0.95
0.018
4
70.0
0.85
0.014
5
85.0
0.80
0.012
Graph of \(I\) (vertical) against \(l^{-1}\) (horizontal):
Line of best fit; intercept on the I-axis (l^-1 = 0) gives I = 0.66 A.
Deduction from the graph. The line of best fit cuts the vertical axis (where \(l^{-1}=0\)) at
\[ I = 0.66\ \text{A}. \]
Hence
\[ \frac{I_0}{I} = \frac{0.8}{0.66} = 1.21. \]
Two precautions:
The key was left open whenever readings were not being taken, to prevent heating of the wire.
The jockey was pressed firmly but was not rolled along or allowed to scratch the potentiometer wire.
(b)(i) Potential difference
The potential difference between two points in an electric circuit is the work done (energy converted from electrical form to other forms) in moving one coulomb of charge from one point to the other:
The circuit is connected as shown, with the standard resistor \(R\) and the ammeter in series with the length \(XC=l\) of the potentiometer wire. With the jockey off the wire the ammeter reads \(I_0\); when the jockey contacts XY at C the current \(I\) is read for each length \(l\), and \(l^{-1}\) is evaluated.
Circuit: cell E, key K and ammeter A in series with the standard resistor R and the length XC = l of the potentiometer wire; jockey J makes contact at C.
Table of readings (\(I_0 = 0.8\ \text{A}\))
S/N
\(l\) (cm)
\(I\) (A)
\(l^{-1}\) (cm\(^{-1}\))
1
25.0
1.20
0.040
2
40.0
1.00
0.025
3
55.0
0.95
0.018
4
70.0
0.85
0.014
5
85.0
0.80
0.012
Graph of \(I\) (vertical) against \(l^{-1}\) (horizontal):
Line of best fit; intercept on the I-axis (l^-1 = 0) gives I = 0.66 A.
Deduction from the graph. The line of best fit cuts the vertical axis (where \(l^{-1}=0\)) at
\[ I = 0.66\ \text{A}. \]
Hence
\[ \frac{I_0}{I} = \frac{0.8}{0.66} = 1.21. \]
Two precautions:
The key was left open whenever readings were not being taken, to prevent heating of the wire.
The jockey was pressed firmly but was not rolled along or allowed to scratch the potentiometer wire.
(b)(i) Potential difference
The potential difference between two points in an electric circuit is the work done (energy converted from electrical form to other forms) in moving one coulomb of charge from one point to the other: