In how many ways can a committee of 5 be selected from 8 students if 2 particular students are to be included?

In how many ways can a committee of 5 be selected from 8 students if 2 particular students are to be included?

Answer Details

Since 2 particular students must be on the committee, we only need to select 3 more students from the remaining 6 students. The number of ways to do this is the number of combinations of 3 students from a set of 6, which is given by: \(\binom{6}{3}=\frac{6!}{3!3!}=20\) Therefore, the answer is 20.