We can rewrite \(8^x\) as \((2^3)^x = 2^{3x}\). Substituting this into the equation, we have:
$$4(2^{x^2}) = 2^{3x}$$
Dividing both sides by \(2^{x^2}\) and simplifying, we get:
$$2^{x^2 - 3x + 2} = 0$$
Using the zero-product property of multiplication, we can set the exponent equal to zero:
$$x^2 - 3x + 2 = 0$$
Factoring the quadratic, we get:
$$(x-1)(x-2) = 0$$
Therefore, the solutions are \(x=1\) and \(x=2\). Hence, the answer is (1, 2).