The sum, \(S_{n}\), of a sequence is given by \(S_{n} = 2n^{2} - 5\). Find the 6th term.

Assessment: WAEC SSCE - Further Mathematics - 2015 (Objective) Subject: Further Mathematics

Question 1 Report

The sum, \(S_{n}\),  of a sequence is given by \(S_{n} = 2n^{2} - 5\). Find the 6th term.

Answer Details
To find the 6th term of the sequence, we need to find the difference between the sum of the first 6 terms and the sum of the first 5 terms. The sum of the first 5 terms is: $S_5 = 2(5)^2 - 5 = 45$ The sum of the first 6 terms is: $S_6 = 2(6)^2 - 5 = 67$ Therefore, the 6th term of the sequence is: $S_6 - S_5 = 67 - 45 = 22$ So the answer is 22.

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