In the figure, PS = RS = QS and QRS = 50o. Find QPR

In the figure, PS = RS = QS and QRS = 50o. Find QPR

Answer Details

In the figure PS = RS = QS, they will have equal base QR = RP

In angle SQR, angle S = 50O

In angle QRP, 65 + 65 = 130O

Since RQP = angle RPQ = $\frac{180-130}{2}$

= $\frac{50}{2}={25}^o$

QPR = 25O