Question 1 Report
If \( \cos^2 \theta + \frac{1}{8} = \sin^2 \theta \), find \( \tan \theta \)
Answer Details
cos2θ θ + 18 1 8 = sin2θ θ ..........(i) from trigometric ratios for an acute angle, where cosθ θ + sin2θ θ = 1 - cosθ θ ........(ii) Substitute for equation (i) in (i) = cos2θ θ + 18 1 8 = 1 - cos2θ θ = cos2θ θ + cos2θ θ = 1 - 18 1 8 2 cos2θ θ = 78 7 8 cos2θ θ = 72×3 7 2 × 3 716 7 16 = cosθ θ √716 7 16 = √74 7 4 but cos θ θ = adjhyp adj hyp opp2 = hyp2 - adj2 opp2 = 42 (√7 7 )2 = 16 - 7 opp = √9 9 = 3 than θ θ = opphyp opp hyp = 3√7 3 7 3√7 3 7 x 7√7 7 7 = 3√77
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