Given that 3x - 5y - 3 = 0, 2y - 6x + 5 = 0 the value of (x, y) is

Assessment: JAMB UTME - Mathematics - 1988 Subject: General Mathematics

Question 1 Report

(

\frac{- 1}{8}, \frac{19}{24}

)

8,

\frac{24}{19}

-8,

\frac{24}{19}

(

\frac{19}{24}, \frac{- 1}{8}

)

Answer Details

3x - 5y = 3, 2y - 6x = -5
-5y + 3x = 3........{i} x 2
2y - 6x = -5.........{ii} x 5
Substituting for x in equation (i)
-5y + 3( $\frac{19}{24}$ ) = 3
-5y + 3 x $\frac{19}{24}$ = 3
-5y = $\frac{3 - 19}{8}$
-5 = $\frac{24 - 19}{8}$
= $\frac{5}{8}$
y = $\frac{5}{8 \times 5}$
y = $\frac{- 1}{8}$
(x, y) = ( $\frac{19}{24}, \frac{- 1}{8}$ )

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Algebraic Expressions

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