If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))
Question 1 Report
If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log (\(\frac{28}{3}\))
Answer Details
We can use logarithmic rules to solve this question. Let's first express log(\(\frac{28}{3}\)) in terms of x, y, and z.
log(\(\frac{28}{3}\)) = log(28) - log(3)
We know that:
log(28) = log(4 × 7) = log(4) + log(7) = 2x + z
log(3) = y
Therefore:
log(\(\frac{28}{3}\)) = 2x + z - y
So the correct answer is 2x + z - y.
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