The mass of one Avogadro number of helium atoms is?

Answer Details

The mass of one Avogadro number of helium atoms is 4.00 grams. Avogadro's number is a fundamental constant in physics and chemistry, and it represents the number of atoms or molecules in one mole of a substance. One mole of a substance is defined as the amount of a substance that contains the same number of entities (atoms, molecules, or other particles) as there are in 12 grams of pure carbon-12. The mass of one Avogadro number of helium atoms depends on the atomic mass of helium, which is approximately 4 atomic mass units. Therefore, one Avogadro number of helium atoms weighs approximately 4 grams.