Given that cos xo = \(\frac{1}{r}\), express tan x in terms of r

Assessment: WAEC SSCE - General Mathematics - 2011 (Objective) Subject: General Mathematics

Question 1 Report

Given that cos x^o = \(\frac{1}{r}\), express tan x in terms of r

\(\frac{1}{\sqrt{r}}\)

\(\sqrt{r}\)

\(\sqrt{r^2 + 1}\)

\(\sqrt{r^2 - 1}\)

Answer Details

We know that: cos x = adjacent side/hypotenuse So, if cos x = 1/r, then adjacent side = 1 and hypotenuse = r. Using the Pythagorean theorem, we can find the opposite side: opposite side = √(hypotenuse^2 - adjacent side^2) = √(r^2 - 1) Finally, we can find the value of tan x: tan x = opposite side/adjacent side = √(r^2 - 1)/1 = √(r^2 - 1) Therefore, the answer is (d) \(\sqrt{r^2 - 1}\).

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Given that cos xo = \(\frac{1}{r}\), express tan x in terms of r

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