Two bodies of masses 3.0 kg and 2.0 kg are separated by a distance of 50 cm. Calculate the force of attraction between them. [G = 6.67 x 10\(^{-11}\) Nm\(^2...
Two bodies of masses 3.0 kg and 2.0 kg are separated by a distance of 50 cm. Calculate the force of attraction between them. [G = 6.67 x 10\(^{-11}\) Nm\(^2\) kg\(^2\)]
Answer Details
We can use the formula for gravitational force between two masses:
F = (G x m1 x m2)/r^2
where
F = force of attraction
G = gravitational constant
m1 and m2 = masses of the bodies
r = distance between the centers of the two bodies
Plugging in the given values, we get:
F = (6.67 x 10^-11 Nm^2/kg^2) x (3.0 kg) x (2.0 kg) / (0.50 m)^2
F = 1.6 x 10^-9 N
Therefore, the force of attraction between the two bodies is 1.6 x 10^-9 N.
Answer: 1.6 x 10^-9 N