he stylus of a phonograph record exerts a force of 7.7 x 10-2N on a groove of radius 10-5m. Compute the pressure exerted by the stylus on the groove
Question 1 Report
he stylus of a phonograph record exerts a force of 7.7 x 10-2N on a groove of radius 10-5m. Compute the pressure exerted by the stylus on the groove
Answer Details
The pressure exerted by the stylus on the groove can be computed using the formula:
pressure = force / area
where force is the force exerted by the stylus on the groove, and area is the contact area between the stylus and the groove.
We are given that the force exerted by the stylus is 7.7 x 10^-2 N, and the radius of the groove is 10^-5 m. The contact area between the stylus and the groove is the area of a circle with radius 10^-5 m, which is given by:
area = πr^2 = π(10^-5)^2 = 3.14 x 10^-10 m^2
Substituting the values into the formula, we get:
pressure = 7.7 x 10^-2 N / 3.14 x 10^-10 m^2 = 2.45 x 10^8 N/m^2
Therefore, the pressure exerted by the stylus on the groove is 2.45 x 10^8 N/m^2. The correct option is "2.45 x 10^8 N/m^2."
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