An organic pipe closed at one end is 80cm long. Determine the frequency of the fundamental note assuming that the speed of sound in air is 340ms-1

Answer Details

The frequency of the fundamental note of an organic pipe closed at one end can be calculated using the formula: f = v/4L Where: f = frequency of the fundamental note v = speed of sound in air L = length of the pipe Given: v = 340ms-1 L = 80cm = 0.8m (since the pipe is closed at one end, we need to consider only its effective length, which is half of its total length) Substituting the values in the formula, we get: f = (340ms-1)/(4 x 0.8m) = 106.25Hz Therefore, the frequency of the fundamental note is 106Hz (approximately), which is closest to option A. Explanation: When we blow into a pipe, the air inside the pipe starts to vibrate, producing sound waves. The sound waves that are produced depend on the length of the pipe, the speed of sound in air, and the boundary conditions of the pipe (whether it is open or closed at one or both ends). In the case of an organic pipe closed at one end, the fundamental frequency is the lowest frequency that can be produced, and it corresponds to the wavelength of twice the effective length of the pipe. Using the formula mentioned above, we can calculate the frequency of the fundamental note.