The empirical formula of an organic liquid hydrocarbon is XY. If the relative molar masses of X and Y are 72 and 6 respectively, it's vapour density is like...

Assessment: JAMB UTME - Chemistry - 2024 Subject: Chemistry

Question 1 Report

The empirical formula of an organic liquid hydrocarbon is XY. If the relative molar masses of X and Y are 72 and 6 respectively, it's vapour density is likely to be
Answer Details

To determine the vapor density of the organic liquid hydrocarbon with the empirical formula XY, we first need to determine the **molecular formula** of the compound, which represents the actual number of atoms of each element in a molecule.


The **relative molar masses** of X and Y are given as 72 and 6, respectively. To find the molar mass of XY, we can add these values together:


Molar mass of XY = Molar mass of X + Molar mass of Y = 72 + 6 = 78 g/mol


Vapor density is defined as half of the molar mass of the compound, since vapor density is often compared to hydrogen, where hydrogen is taken as the standard with a molar mass of 2 g/mol. Therefore, vapor density can be calculated using the formula:


Vapor Density = (Molar Mass of the Compound) / 2


Substituting the molar mass of XY:


Vapor Density of XY = 78 / 2 = 39


Therefore, the vapor density of the hydrocarbon with the empirical formula XY is **39**.

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