The volume occupied by 1 mole of an ideal gas at a temperature of 130 0 C and a pressure of 1.58 atm is [ R = 0.082 atm dm3 3 K−1 − 1 mol−1 − 1 ]

Question 1 Report

The volume occupied by 1 mole of an ideal gas at a temperature of 13 $^{0}$ C and a pressure of 1.58 atm is

[ R = 0.082 atm dm $^{3}$ K $^{- 1}$ mol $^{- 1}$ ]

14.84 dm

^{3}

14.84 cm

^{3}

0.64 dm

^{3}

0.64 cm

^{3}

Answer Details

According to the Ideal gas equation, PV = nRT

Given: P = 1.58 atm, V = ?, n = 1 mole, R = 0.082, T= 13 + 273K = 286K

Substituting all the given parameters,

V = $\frac{n R T}{P}$

V = $\frac{1 \times 0.082 \times 286}{1.58}$

V = 14.84 dm $^{3}$

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