127g of sodium chloride was dissolved in 1.0dm3 3 of distilled water at 250 0 C . Determine the solubility in moldm−3 − 3 of sodium chloride at that tempera...

Assessment: JAMB UTME - Chemistry - 2024 Subject: Chemistry

Question 1 Report

127g of sodium chloride was dissolved in 1.0dm3 3  of distilled water at 250 0 C . Determine the solubility in moldm−3 − 3  of sodium chloride at that temperature. [Na = 23, Cl = 35.5] 
Answer Details

To determine the solubility of sodium chloride (NaCl) in mol/dm3 at the given temperature, you need to first calculate the number of moles of NaCl dissolved.


Step 1: Calculate the molar mass of NaCl.

The molar mass of a compound is found by adding the atomic masses of its constituent elements:

- Sodium (Na) has an atomic mass of 23.

- Chlorine (Cl) has an atomic mass of 35.5.

Thus, the molar mass of NaCl = 23 + 35.5 = 58.5 g/mol.


Step 2: Calculate the number of moles of NaCl.

The formula to calculate moles is:

Number of moles = Mass (g) / Molar mass (g/mol)

Given mass of NaCl = 127 g,

Number of moles = 127 g / 58.5 g/mol ≈ 2.17 mol


Step 3: Calculate the solubility in mol/dm3.

Since the sodium chloride is dissolved in 1.0 dm3 of water, the solubility is the same as the number of moles, since the volume is already 1.0 dm3.


Therefore, the solubility of sodium chloride at that temperature is 2.17 mol/dm3.


Rounded to the options given, 2.17 mol/dm3 is approximately equal to 2.2 mol/dm3.

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