Determine the half-life of a first order reaction with constant 4.5 x 10−3 − 3 sec−1 − 1 .

Assessment: JAMB UTME - Chemistry - 2024 Subject: Chemistry

Question 1 Report

Determine the half-life of a first order reaction with constant 4.5 x 10

^{- 3}

sec

^{- 1}

154 s

15.4 s

1540 s

1.54 s

Answer Details

To determine the half-life of a first-order reaction, you can use the formula:

Half-life (\(t_{1/2}\)) = \(\frac{0.693}{k}\)

where \(k\) is the rate constant of the reaction. For the given problem, the rate constant (\(k\)) is 4.5 x 10^-3 s^-1.

Substituting the value of \(k\) into the formula, we have:

\(t_{1/2} = \frac{0.693}{4.5 \times 10^{-3}}\)

Perform the division:

\(t_{1/2} = \frac{0.693}{4.5 \times 10^{-3}} \approx 154\) s

Therefore, the half-life of the reaction is 154 seconds.

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