200 tickets were sold for a show. VIP tickets costs ₦1,200 and ₦700 for regular. Total amount realised from the sale of the tickets was ₦180,000. Find the n...
200 tickets were sold for a show. VIP tickets costs ₦1,200 and ₦700 for regular. Total amount realised from the sale of the tickets was ₦180,000. Find the number of VIP tickets sold and the the number of regular ticket sold.
Answer Details
To find the number of VIP tickets sold and the number of regular tickets sold, we can set up a system of equations based on the information given.
Let's assume that the number of VIP tickets sold is represented by 'V' and the number of regular tickets sold is represented by 'R'.
From the information given, we know that a total of 200 tickets were sold. Therefore, we can write the equation:
V + R = 200 -------------- (Equation 1)
We also know that VIP tickets cost ₦1,200 and regular tickets cost ₦700. The total amount realized from the sale of the tickets was ₦180,000. So, we can write another equation based on the ticket prices and total amount:
1200V + 700R = 180,000 -------------- (Equation 2)
Solving these two equations will give us the values of V (VIP tickets) and R (regular tickets).
To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of substitution:
1. Solve Equation 1 for V in terms of R: V = 200 - R
2. Substitute this value of V in Equation 2: 1200(200 - R) + 700R = 180,000
Simplify the equation: 240,000 - 1200R + 700R = 180,000
Combine like terms: 500R = 60,000
Divide both sides by 500: R = 120
Now, we know the number of regular tickets sold is 120. We can substitute this value back into Equation 1 to find the number of VIP tickets:
V + 120 = 200
Subtract 120 from both sides: V = 200 - 120 V = 80
Therefore, the number of VIP tickets sold is 80 and the number of regular tickets sold is 120.
The correct answer is: VIP = 80, Regular = 120