If 50 cm3 3 of a saturated solution of KNO3 3 at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be [KNO3 3 = 101]

Assessment: WAEC SSCE - Chemistry - 2022 Subject: Chemistry

Question 1 Report

If 50 cm $^{3}$ of a saturated solution of KNO $_{3}$ at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be
[KNO $_{3}$ = 101]

1.0 mol dm-3

1.5 mol dm

^{- 3}

2.0 mol dm

^{- 3}

5.0 mol dm

^{- 3}

Answer Details

V= 50cm $^{3}$
Mass= 5.05g
Relative molecular mass of KNO $_{3}$ = (39+14+(3*16)) = 101
Convert 50cm $^{3}$ to dm $^{3}$ which is
1000cm³ = 1dm $^{3}$
50cm³ = 50*1/1000
= 0.05dm $^{3}$
Moles = mass/ molar mass
= 5.05/101 =0.05mole
Solubility= mole/volume
Solubility=0.05mol/0.05dm $^{3}$
Solubility=1.0mol/dm_ $^{3}$

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

Solubility Of Substances (Ghana Only)

View Answer

If 50 cm3 3 of a saturated solution of KNO3 3 at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be [KNO3 3 = 101]

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