If \(50\ \text{cm}^3\) of a saturated solution of \(\mathrm{KNO_3}\) at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be ...

Assessment: WAEC SSCE - Chemistry - 2022 (Objective) Subject: Chemistry

Question 1 Report

If \(50\ \text{cm}^3\) of a saturated solution of \(\mathrm{KNO_3}\) at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be

[\(\mathrm{KNO_3}\) = 101]

1.0 mol dm-3

1.5 mol dm

^{- 3}

2.0 mol dm

^{- 3}

5.0 mol dm

^{- 3}

Answer Details

V= 50cm

^{3}

Mass= 5.05g
Relative molecular mass of KNO

_{3}

= (39+14+(3*16)) = 101
Convert 50cm

^{3}

to dm

^{3}

which is
1000cm³ = 1dm

^{3}

50cm³ = 50*1/1000
= 0.05dm

^{3}

Moles = mass/ molar mass
= 5.05/101 =0.05mole
Solubility= mole/volume
Solubility=0.05mol/0.05dm

^{3}

Solubility=1.0mol/dm_

^{3}

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

Solubility Of Substances (Ghana Only)

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If \(50\ \text{cm}^3\) of a saturated solution of \(\mathrm{KNO_3}\) at 40 °C contained 5:05 g of the salt, its solubility at the same temperature would be ...

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