If the molar mass of X(HCO3)2 2 is 162 g mol−1 − 1 , determine the relative atomic mass of X. [H = 1.0, C = 12.0, 0 = 16.0]

If the molar mass of X(HCO3)2 ${}_2$ is 162 g mol−1 ${}^{-1}$, determine the relative atomic mass of X.
[H = 1.0, C = 12.0, 0 = 16.0]

Answer Details

The molar mass of X(HCO3)2 can be calculated by adding up the atomic masses of all the atoms in one mole of the compound. One mole of X(HCO3)2 contains: - 2 moles of hydrogen (2 x 1.0 = 2.0) - 2 moles of carbon (2 x 12.0 = 24.0) - 6 moles of oxygen (6 x 16.0 = 96.0) - 1 mole of X The total molar mass is then: 2.0 + 24.0 + 96.0 + m(X) = 162 g/mol Solving for m(X), we get: m(X) = 162 g/mol - 2.0 - 24.0 - 96.0 m(X) = 40 g/mol Therefore, the relative atomic mass of X is 40, which corresponds to the atomic mass of the element with the symbol Ca (calcium). Therefore, option A is the correct answer.