What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm3 3 cylinder? [R=0.082 atm dm−3 − 3 mol−1 − 1 K−1 − 1 ]

What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm3 ${}^3$ cylinder?
[R=0.082 atm dm−3 ${}^{-3}$ mol−1 ${}^{-1}$ K−1 ${}^{-1}$]

Answer Details

P = 10atm, T= 320K, V= 8.2dm3 ${}^3$
PV =nRT
n = P * V/R * T
10 * 8.2/0.082 * 320
= 82/26.24
n = 3.13