What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{3}\) cylinder? [R=0.082 atm dm\(^{-3}\) mol\(^{-1}\) K\(^{-1}\)]

Assessment: WAEC SSCE - Chemistry - 2022 (Objective) Subject: Chemistry

Question 1 Report

What number of moles of oxygen would exert a pressure of 10 atm at 320 K in an 8.2 dm\(^{3}\) cylinder?

[R=0.082 atm dm\(^{-3}\) mol\(^{-1}\) K\(^{-1}\)]

Answer Details
P = 10atm, T= 320K, V= 8.2dm3 3
PV =nRT
n = P * V/R * T
10 * 8.2/0.082 * 320
= 82/26.24
n = 3.13

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