What is the partial pressure of oxygen at s.t.p. in a gaseous mixture containing 100 cm3 of oxygen and 900 cm3 of nitrogen gas?
Answer Details
At s.t.p (standard temperature and pressure), the pressure is 1 atmosphere (1 atm) and the temperature is 0 degrees Celsius (273.15 K).
In the given gaseous mixture, the partial pressure of oxygen can be calculated using the following formula:
Partial pressure of oxygen = Total pressure x Volume fraction of oxygen
The total pressure of the mixture is 1 atm.
The volume fraction of oxygen can be calculated by dividing the volume of oxygen by the total volume of the mixture:
Volume fraction of oxygen = Volume of oxygen / Total volume of mixture
Volume fraction of oxygen = 100 cm3 / (100 cm3 + 900 cm3)
Volume fraction of oxygen = 0.1
Substituting these values in the formula, we get:
Partial pressure of oxygen = 1 atm x 0.1
Partial pressure of oxygen = 0.1 atm
Therefore, the partial pressure of oxygen in the given gaseous mixture is 0.1 atm. is the correct answer.