What is the partial pressure of oxygen at s.t.p. in a gaseous mixture containing 100 cm3 of oxygen and 900 cm3 of nitrogen gas?

At s.t.p (standard temperature and pressure), the pressure is 1 atmosphere (1 atm) and the temperature is 0 degrees Celsius (273.15 K). In the given gaseous mixture, the partial pressure of oxygen can be calculated using the following formula: Partial pressure of oxygen = Total pressure x Volume fraction of oxygen The total pressure of the mixture is 1 atm. The volume fraction of oxygen can be calculated by dividing the volume of oxygen by the total volume of the mixture: Volume fraction of oxygen = Volume of oxygen / Total volume of mixture Volume fraction of oxygen = 100 cm3 / (100 cm3 + 900 cm3) Volume fraction of oxygen = 0.1 Substituting these values in the formula, we get: Partial pressure of oxygen = 1 atm x 0.1 Partial pressure of oxygen = 0.1 atm Therefore, the partial pressure of oxygen in the given gaseous mixture is 0.1 atm. is the correct answer.