The angles of a pentagon are x°, 2x°, (x + 60)°, (x + 10)°, (x -10)°. Find the value of x.

Assessment: WAEC SSCE - General Mathematics - 1991 (Objective) Subject: General Mathematics

Question 1 Report

The angles of a pentagon are x°, 2x°, (x + 60)°, (x + 10)°, (x -10)°. Find the value of x.

Answer Details

In a pentagon, the sum of the angles is equal to (5 - 2) times 180 degrees, which is 540 degrees. So we can set up an equation to solve for x:

x + 2x + (x + 60) + (x + 10) + (x - 10) = 540

Simplifying this equation, we get:

6x + 60 = 540

Subtracting 60 from both sides, we get:

6x = 480

Dividing both sides by 6, we get:

x = 80

Therefore, the value of x is 80. So, the correct answer is:

80
View Answer

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