The first term a of an A.P is equal to twice the common difference d. Find, in terms of d, the 5th term of the A.P.

In an arithmetic progression (A.P), the difference between any two consecutive terms is constant. Let's call this constant difference "d". We're told that the first term "a" is equal to twice the common difference, so: a = 2d To find the 5th term of the A.P, we can use the formula: an = a + (n-1)d where "an" is the nth term of the A.P. Substituting the given values, we get: a5 = 2d + (5-1)d a5 = 2d + 4d a5 = 6d Therefore, the 5th term of the A.P is 6d. Answer: 6d.