Factorize 3a\(^2\) - 11a + 6

To factorize 3a\(^2\) - 11a + 6, we need to find two binomials that, when multiplied together, result in the original expression. To do this, we can use a technique called "factoring by grouping." First, we need to identify two numbers that multiply to 3 x 6 = 18 and add up to -11. These numbers are -2 and -9. Next, we can split the middle term -11a into -2a - 9a, and then group the terms as follows: 3a\(^2\) - 2a - 9a + 6 Now, we can factor out the greatest common factor from the first two terms, and the greatest common factor from the last two terms: a(3a - 2) - 3(3a - 2) Notice that we have a common binomial factor of (3a - 2), which we can factor out: (3a - 2)(a - 3) Therefore, the correct option is (3a - 2)(a - 3).