What is the change in the oxidation number of 1- in the reaction represented by the following equation? 51 -1(aq) + 6H+(aq) + 1O-3(aq) → 312(g) + 3H2O(l)

What is the change in the oxidation number of 1^- in the reaction represented by the following equation? 51 ^-1_(aq) + 6H⁺_(aq) + 1O^-_3(aq) → 31_2(g) + 3H₂O_(l)

Answer Details

The oxidation number of an ion is the charge of the ion. The oxidation number of 1^- is -1. In the equation, the reactant 51 ^-1_(aq) is being oxidized because its oxidation number is changing from -1 to 0. Thus, the change in the oxidation number of 1^- is from -1 to 0, which means an increase in oxidation number or a loss of electrons. Therefore, the answer is -1 to 0.