Numbers123456Frequency182220161014 Numbers 1 2 3 4 5 6 Frequency 18 22 20 16 10 14 The table above represents the outcome of throwing a die 100 times. What ...

$\begin{array}{ccccccc}\text{Numbers}& 1& 2& 3& 4& 5& 6\\ \text{Frequency}& 18& 22& 20& 16& 10& 14\end{array}$

The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?

Answer Details

Let E demote the event of obtaining at least a 4
Then n(E) = 16 + 10 + 14 = 40
Hence, prob (E) = $\frac{n\left(E\right)}{n\left(S\right)}$
$=\frac{40}{100}$
$=\frac{2}{5}$