An organic compound which reacts readily with bromine to form a compound with the formula CH3CHBrCH2Br is

Assessment: WAEC SSCE - Chemistry - 1991 (Objective) Subject: Chemistry

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An organic compound which reacts readily with bromine to form a compound with the formula CH3CHBrCH2Br is
Answer Details
The organic compound which reacts readily with bromine to form a compound with the formula CH3CHBrCH2Br is propene. Propene is an unsaturated hydrocarbon with the chemical formula C3H6. It contains a carbon-carbon double bond that is readily attacked by bromine in the presence of an appropriate catalyst. The addition of two bromine atoms across the double bond of propene produces 2-bromopropane, which has the formula CH3CHBrCH2Br. This reaction is an example of electrophilic addition, in which an electrophile (in this case, Br2) is added to an unsaturated molecule (propene) to form a saturated molecule (2-bromopropane). Therefore, propene is the organic compound that reacts readily with bromine to form 2-bromopropane.
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