The products of the reaction between CH3CH 2COOH and CH3OH are H 2 O and
Answer Details
The products of the reaction between CH3CH 2COOH (propanoic acid) and CH3OH (methanol) are CH 3CH2COOCH3 (methyl propanoate) and H2O (water). This is an esterification reaction where the carboxylic acid (propanoic acid) reacts with an alcohol (methanol) in the presence of an acid catalyst (such as sulfuric acid) to form an ester (methyl propanoate) and water. The general equation for this reaction is: R-COOH + R'-OH ⇌ R-COOR' + H2O In this specific case, the reaction between propanoic acid and methanol produces methyl propanoate and water as the products.