A body of mass 5kg moving with a velocity of 10ms-1 collides with a stationary body of mass 6kg. If the two bodies stick together and move in the same direc...

Answer Details

To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it. In this case, the initial momentum of the system is: p_i = m₁v₁ + m₂v₂ where m₁ and v₁ are the mass and velocity of the first body, and m₂ and v₂ are the mass and velocity of the second body. Substituting the given values, we get: p_i = (5 kg)(10 m/s) + (6 kg)(0 m/s) = 50 kg m/s After the collision, the two bodies stick together and move with a common velocity, which we can call v_f. Using the law of conservation of momentum again, we can write: p_f = (m₁ + m₂)v_f where p_f is the final momentum of the system. Since no external forces act on the system, the initial and final momenta must be equal: p_i = p_f Substituting the values we obtained earlier and solving for v_f, we get: 50 kg m/s = (5 kg + 6 kg)v_f v_f = 4.55 m/s Therefore, the common velocity of the two bodies after the collision is 4.55 m/s. Answer is correct.