An object is projected with a velocity of 100 ms-1 from the ground level at an angle 0 to the vertical. If the total time of flight of the projectile is 10 ...
Question 1 Report
An object is projected with a velocity of 100 ms-1 from the ground level at an angle 0 to the vertical. If the total time of flight of the projectile is 10 s, calculate θ. (g = 10 ms-2).
Answer Details
When an object is projected at an angle to the vertical, it moves in a curved path called a projectile motion. The horizontal and vertical motions of the projectile are independent of each other. The time of flight is the total time taken by the projectile to reach the maximum height and return to the ground level.
Let's denote θ as the angle of projection. We can use the following equations to solve for θ:
Time of flight = 2usinθ/g
where u is the initial velocity and g is the acceleration due to gravity.
In this case, u = 100 ms^-1 and the time of flight = 10 s.
Therefore, 10 = 2 x 100 x sinθ / 10
Simplifying, we get sinθ = 0.5
To find θ, we take the inverse sine (sin^-1) of 0.5, which gives us θ = 30°.
Therefore, the answer is θ = 30°.
Download The App On Google Playstore
Everything you need to excel in your exams
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning