In a purely resistive a.c. circuit, the current I = Io sin wt and voltage, V = Vo sin wt. Calculate the instantaneous power dissipated in the circuit in tim...

In a purely resistive a.c. circuit, the current I = I_o sin wt and voltage, V = V_o sin wt. Calculate the instantaneous power dissipated in the circuit in time t.

Answer Details

The instantaneous power P in a purely resistive AC circuit is given by the formula P = VI, where V is the voltage and I is the current in the circuit. In this case, we have I = I_o sin wt and V = V_o sin wt, so we can substitute these values into the formula to get: P = VI = (I_o sin wt) (V_o sin wt) Expanding this equation, we get: P = I_o V_o sin²wt Therefore, the answer is (d) I_o V_o sin²wt.