Question 1 Report
Which volume of 0.5 M H 2SO4 will exactly neutralize 20 cm 3 of 0.1 M NaOH solution?
Answer Details
CAVACbVb=12 C A V A C b V b = 1 2
frac0.5×VA0.1×20=12 f r a c 0.5 × V A 0.1 × 20 = 1 2
\(V_A = \frac{0.1 \times 20}{2 \times 0.5} = \frac{1.0}{0.5)\)
= 2cm2